/**
6. Write a function with prototype void fun(double) that prints out an appropriate message depending on the user-entered temperature:

greater than 90 : ``too hot''
75 to 89 : `` hot''
60 to 74 : ``mild''
35 to 60 : ``chilly''
less than 35 : ``cold''

What will happen if you entered a char for the  temperature?

Now use function overloading to allow the user to input the temperature
as well as a char,  'F' for Fahrenheit and 'C' for Celsius, and the
function outputs the appropriate message.

**/

#include<iostream>
using namespace std;

void fun(double&);
void fun(double&, char&);

int main() {
  double a;
  char scale;
  cout <<"Enter temperature"<<endl;
  cin >>a;
  fun(a);
  //Now prompt for temperature and scale
  cout <<endl<<endl<<"Enter temperature and scale"<<endl;
  cin>>a>>scale;  
  fun(a,scale);
  return 0;
}

void fun(double& a){
  if(a>=90){
    cout<<"Too hot"<<endl;
  }
  else if(a>=75){
    cout<<"Hot"<<endl;
  }
  else if(a>=60){
    cout<<"Mild"<<endl;
  }
  else if(a>=35){
    cout<<"Chilly"<<endl;
  }
  else {
    cout<<"Cold"<<endl;
  }
}

void fun(double& a, char& scale){
  if((scale=='F')||(scale=='f')){
    fun(a);
  }
  else if((scale=='C')||(scale=='c')){
    a=a*9.0/5.0+32.0;
    fun(a);
  }
  else {
    cout<<"You must enter scale as 'F' or 'C'"<<endl;
  }
}